Transition and InnerTransition Elements - Result Question 49
50. Potassium manganate $\left(K _2 MnO _4\right)$ is formed when
$(1988,2 M)$
(a) chlorine is passed into aqueous $KMnO _4$ solution
(b) manganese dioxide is fused with $KOH$ in air
(c) formaldehyde reacts with potassium permanganate in the presence of strong alkali
(d) potassium permanganate reacts with conc. $H _2 SO _4$
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Answer:
Correct Answer: 50. (b, c)
Solution:
$2 KOH+MnO _2+O _2 \stackrel{\Delta}{\longrightarrow} K _2 MnO _4+H _2 O$
$HCHO+KMnO _4+2 KOH \longrightarrow K _2 MnO _4+H _2 O$
$$ \quad \quad \quad \quad \quad +HCOOH$$
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