Transition and InnerTransition Elements - Result Question 64
65. A compound of vanadium has a magnetic moment of 1.73 BM. Work out the electronic configuration of the vanadium ion of the compound.
(1997)
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Solution:
$\mu=\sqrt{n(n+2)} BM$ where ’ $n$ ’ is number of unpaired electrons.
$1.73=\sqrt{n(n+2)} \Rightarrow n=1 ; \mathrm{V}^{4+}=3 d^1$
BETA
