Straight Line And Pair Of Straight Lines Ques 23

  1. The incenter of the triangle with vertices $(1, \sqrt{3}),(0,0)$ and $(2,0)$ is

(2000, 2M)

(a) $1, \frac{\sqrt{3}}{2}$

(b) $\frac{2}{3}, \frac{1}{\sqrt{3}}$

(c) $\frac{2}{3}, \frac{\sqrt{3}}{2}$

(d) $1, \frac{1}{\sqrt{3}}$

Show Answer

Solution:

Formula:

Centroid, Incentre and Excentre:

Let the vertices of triangle be $A(1, \sqrt{3}), B(0,0)$ and $C(2,0)$. Here, $AB=BC=CA=2$.

Therefore, it is an equilateral triangle. So, the incentre coincides with centroid.

$$ \begin{array}{ll} \therefore & I \equiv \frac{0+1+2}{3}, \frac{0+0+\sqrt{3}}{3} \\ \Rightarrow & I \equiv(1,1 / \sqrt{3}) \end{array} $$



Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें