Current Electricity Ques 101
- A galvanometer having a resistance of $20 $ $\Omega$ and $ 30$ divisions on both sides has figure of merit $0.005$ ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto $15$ volt is
(2019 Main, 11 Jan II)
(a) $100$ $\Omega$
(b) $125$ $\Omega$
(c) $120$ $\Omega$
(d) $80 $ $ \Omega$
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Answer:
Correct Answer: 101.(d)
Solution:
Formula:
- Resistance of galvanometer, $(G)=20$ $ \Omega$
Number of divisions on both side $=30$
Figure of merit $=0.005$ ampere/division
$\therefore$ Full scale deflection current $\left(I _g\right)$
$=$ Number of divisions $\times$ figure of merit
$ \Rightarrow \quad I _g=30 \times 0.005=0.15$ $ A $
Now, for measuring $15$ $ V$ by this galvanometer, let we use a resistance of $R$ ohm in series with the galvanometer.
$\therefore$ Effective resistance of voltmeter, $R _{\text {eff }}=R+20$
As,maximum potential measured by voltmeter.
or
$ \begin{aligned} & V=I _g \cdot R _{\text {eff }} \text { or } 15=0.15(R+20) \\ & R+20=100 \text { or } R=80 \Omega \end{aligned} $
BETA
