Current Electricity Ques 16
- The current-voltage graphs for a given metallic wire at two different temperatures $T _1$ and $T _2$ are shown in the figure. The temperature $T _2$ is greater than $T _1$
$(1985,3 M)$
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Answer:
Correct Answer: 16.(True)
Solution:
Formula:
- $\frac{I}{V}=$ slope of given graph $=\frac{1}{R} \quad$ or $\quad R=\frac{1}{\text { slope }}$
Resistance of a metallic wire increases with increase in temperature.
$(\text { slope }) _{T _2} <(\text { slope }) _{T _1} $
$\therefore \frac{1}{(\text { slope }) _{T _2}} >\frac{1}{(\text { slope }) _{T _1}} $
$\text { or } \quad R _{T _2} >R _{T _1} \text { or } T _2>T _1$
BETA
