Current Electricity Ques 54
- In the given circuit diagram, the currents $I _1=-0.3$ $A$, $I _4=0.8$ $A$ and $I _5=0.4 $ $A$, are flowing as shown. The currents $I _2, I _3$ and $I _6$ respectively, are
(a) $1.1$ $ A$, $ 0.4$ $ A$, $ 0.4$ $A$
(b) $1.1$ $ A$, $-0.4$ $ A$, $ 0.4$ $A$
(c) $0.4$ $ A$, $ 1.1$ $ A$, $ 0.4$ $A$
(d) $-0.4$ $ A$, $ 0.4$ $ A$, $ 1.1$ $A$
(2019 Main, 10 Jan II)
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Answer:
Correct Answer: 54.(a)
Solution:
- Given circuit with currents as shown in the figure below, [In the question $I_1=0.3$ $A$ is given, due to it we change the direction of $I_1$, in this figure]
From Kirchoff’s junction rule, $\Sigma I=0$
$ \begin{alignedat} & \text { At junction } S, \quad I _4=I _5+I _3 \\ & \Rightarrow \quad 0.8=0.4+I _3 \\ & \Rightarrow \quad I _3=0.4 A \\ & \text { At junction } P, \quad I _5=I _6 \\ & \Rightarrow \quad I _6=0.4 A \\ & \text { At junction } Q, \quad I _2=I _1+I _3+I _4 \\ I =0.3+0.4+0.4=1.1 A \end{aligned} $
BETA
