Current Electricity Ques 55
- In the given circuit, the cells have zero internal resistance. The currents (in Ampere) passing through resistances $R _1$ and $R _2$ respectively are
(2019 Main, 10 Jan I)
(a) $0.5,0$
(b) $1,2$
(c) $2,2$
(d) $0,1$
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Answer:
Correct Answer: 55.(a)
Solution:
- By Kirchhoff’s loop rule in the given loop $A B E F A$, we get
$10-\left(I _1+I _2\right) R _1=0 $
$\Rightarrow \quad 10-\left(I _1+I _2\right) 20=0 $
$ \text { or } \quad I _1+I _2=\frac{1}{2} $$\quad$ …….(i)
and from loop $B C D E B$, we get
$10-\left(I _1+I _2\right) R _1-I _2 R _2 =0 $
$\Rightarrow 10-\left(I _1+I _2+I _2\right) 20 =0 $
$\Rightarrow I _1+2 I _2 =\frac{1}{2}$ $\quad$ …….(ii)
From Eqs. (i) and (ii), we get
$ I _2=0 \text { and } I _1=0.5 A $
BETA
