Current Electricity Ques 67
- A current of $2 mA$ was passed through an unknown resistor which dissipated a power of $4.4 W$. Dissipated power when an ideal power supply of $11 V$ is connected across it is
(a) $11 \times 10^{-4} W$
(b) $11 \times 10^{-5} W$
(c) $11 \times 10^{5} W$
(d) $11 \times 10^{-3} W$
(2019 Main, 10 Jan II)
Show Answer
Solution:
Formula:
- Power dissipated by any resistor $R$, when $I$ current flows through it is $P = I^2R$.
$$ P=I^{2} R $$
Given $I=2 mA=2 \times 10^{-3} A$ and $P=4.4 W$
Using Eq. (i), we get
or
$$
BETA
