Laws Of Motion Ques 20
- A block of mass $0.1 kg$ is held against a wall applying a horizontal force of $5 N$ on the block. If the coefficient of friction between the block and the wall is 0.5 , the magnitude of the frictional force acting on the block is
(1994, 1M)
(a) $2.5 N$
(b) $0.98 N$
(c) $4.9 N$
(d) $0.49 N$
Show Answer
Answer:
Correct Answer: 20.(b)
Solution:
Formula:
- $N=5\ \text{N}$
$(f) _{\max }=\mu N=(0.5)(5)=2.5 N$
For vertical equilibrium of the block,
$f=m g=0.98 N<(f)_{\max}$
BETA
