Laws Of Motion Ques 23
A block of mass $1 \mathrm{~kg}$ lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6 . If the acceleration of the truck is $5 \mathrm{~m} / \mathrm{s}^{2}$, the frictional force acting on the block is $5 \mathrm{~N}$.
$(1984,2 \mathrm{M})$
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Answer:
Correct Answer: 23.(5)
Solution:
Formula:
The block will move due to an applied force.
The frictional force $(f)$ is therefore defined by the equation $f = \mu N$, where $\mu$ is the coefficient of friction and $N$ is the normal force.
$$ f=m a=(1)(5)=5 \mathrm{~N} $$
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