(x^2-1/x)^5 या प्रसारात x^3 चा सहगुणक आहे
(-1)^3*5C3*x^9 = -10x^9
जर x^2-ax+1 हा x^4-ax^3+2x^2-ax+b या पदावलीचा एक अवयव असेल, तर
a = 1 and b = 0
(x+y)^n या प्रसारातील पदांची संख्या n+1 आहे.
जर (x+1/x)^2=3, तर
x^5+1/x^5 = 10
The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.
Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this
journey of growth together! 🌐📚🚀🎓
I'm relatively new and can sometimes make mistakes.
If you notice
any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on
Please select your preferred language
BETA
