A) $ p _0V _0 $
B) $ 2p _0V _0 $
C) $ \frac{p _0V _0}{2} $
D) సున్నా
సరైన సమాధానం: D
చక్రీయ ప్రక్రియలో చేసిన పని = మూసివేయబడిన ఆకృతి చుట్టూ ఉన్న ప్రాంతం
= మూసివేయబడిన ఆకృతి యొక్క వైశాల్యం = $ 2[ \frac{1}{2}(v _{0/2})\times p _0 ]+{ -2[ \frac{1}{2}(v _{0/2})p _0 ] . } $ = సున్నా.
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