Alkyl Halides - Result Question 54
54. In the following monobromination reaction, the number of possible chiral product(s) is (are)…
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Answer:
Correct Answer: 54. $(5)$
Solution:
- Given compound undergoes free-radical bromination under given conditions, replacing $H$ by $Br$.
$C^{*}$ is chiral carbon.
(III) has two chiral centres and can have two structures.
(IV) has also two chiral centres and can have two structures.
It has plane of symmetry thus, achiral.
Thus, chiral compounds are five. I, III A, III B, IV B and V.
BETA
