Carboxylic Acids and their Derivatives - Result Question 11
11. When propionic acid is treated with aqueous sodium bicarbonate, $CO _2$ is liberated. The $C$ of $CO _2$ comes from
$(1999,2 M)$
(a) methyl group
(b) carboxylic acid group
(c) methylene group
(d) bicarbonate group
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Answer:
Correct Answer: 11. (d)
Solution:
$ CH _3-CH _2-COOH + NaH \stackrel{*}C O _3 \longrightarrow CH _3 CH _2 COONa + H _2 O + \stackrel{*}C O _2 $
BETA
