Carboxylic Acids and their Derivatives - Result Question 3
3. The compound that does not liberate $CO _2$, on treatment with aqueous sodium bicarbonate solution, is
(2013 Adv.)
(a) benzoic acid
(b) benzenesulphonic acid
(c) salicylic acid
(d) carbolic acid (Phenol)
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Answer:
Correct Answer: 3. (d)
Solution:
PLAN: $NaHCO _3 \rightleftharpoons Na^{+}+HCO _3^{-}$
$HCO _3^{-}$ is decomposed by acid releasing $CO _2$
$HCO _3^{-}+H^{+} \longrightarrow H _2 O+CO _2$
If acid is stronger than $HCO _3^{-}$ then $CO _2$ is released. Phenol is less acidic and thus does not liberate $CO _2$ with $NaHCO _3$.
BETA
