Carboxylic Acids and their Derivatives - Result Question 36
Passage
$P$ and $Q$ are isomers of dicarboxylic acid $\mathrm{C}_4 \mathrm{H}_4 \mathrm{O}_4$. Both decolourize $\mathrm{Br}_2 / \mathrm{H}_2 \mathrm{O}$. On heating, $P$ forms the cyclic anhydride. Upon treatment with dilute alkaline $\mathrm{KMnO}_4 \cdot P$ as well as $Q$ could produce one or more than one form $S, T$ and $U$.
(2013 Adv.)
23. Compounds formed from $P$ and $Q$ are, respectively
(a) Optically active $S$ and optically active pair $(T, U)$
(b) Optically inactive $S$ and optically inactive pair $(T, U)$
(c) Optically active pair $(T, U)$ and optically active $S$
(d) Optically inactive pair $(T, U)$ and optically inactive $S$
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Answer
Correct answer: 23. (b)
Solution:
BETA
