Carboxylic Acids and their Derivatives - Result Question 39
Passage
$R \mathrm{CONH}_2$ is converted into $R \mathrm{NH}_2$ by means of Hofmann’s bromamide degradation.
In this reaction, $R \mathrm{CONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann’s degradation reaction is an intramolecular reaction.
$(2006,3 \times 4 M=12 M)$
25. How can the conversion of (i) to (ii) be brought about?
(a) $KBr$
(b) $KBr+CH _3 ONa$
(c) $KBr+KOH$
(d) $Br _2+KOH$
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Answer:
Correct Answer: 25. (d)
Solution:
BETA
