Chemical and Ionic Equilibrium - Result Question 17
17. $Ag^{+}+NH _3 \rightleftharpoons\left[Ag\left(NH _3\right)\right]^{+} ; K _1=3.5 \times 10^{-3}$
$\left[Ag\left(NH _3\right)\right]^{+}+NH _3 \rightleftharpoons\left[Ag\left(NH _3\right) _2\right]^{+} ; K _2=1.7 \times 10^{-3}$
then the formation constant of $\left[Ag\left(NH _3\right) _2\right]^{+}$is
(2006,3 M)
(a) $6.08 \times 10^{-6}$
(b) $6.08 \times 10^{6}$
(c) $6.08 \times 10^{-9}$
(d) None of these
Show Answer
Answer:
Correct Answer: 17. (a)
Solution:
- $Ag^{+}+NH _3 \rightleftharpoons\left[Ag\left(NH _3\right)^{+}\right]$ $\hspace {15mm}$ $K _1=3.5 \times 10^{-3}$
$\dfrac {\left[Ag\left(NH _3\right)^{+}\right]+NH _3 \rightleftharpoons\left[Ag\left(NH _3\right) _2^{+}\right] \quad K _2=1.7 \times 10^{-3}}{Adding : Ag^{+}+2 NH _3 \rightleftharpoons\left[Ag\left(NH _3\right) _2^{+}\right]}$
$K=K _1 \times K _2=5.95 \times 10^{-6}$
BETA
