Chemical And Ionic Equilibrium Result Question 27
27. The conjugate acid of $\mathrm{NH} _2^{-}$is
(1985, 1M)
(a) $\mathrm{NH} _3$
(b) $\mathrm{NH} _2 \mathrm{OH}$
(c) $\mathrm{NH} _4^{+}$
(d) $\mathrm{N} _2 \mathrm{H} _4$
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Answer:
Correct Answer: 27. ( a )
Solution:
$ \underset{\text { Base }}{\mathrm{NH}_2^{-}}+\mathrm{H}_2 \mathrm{O} \rightleftharpoons \underset{\text { Conjugate acid }}{\mathrm{NH}_3}+\mathrm{OH}^{-} $
BETA
