Chemical And Ionic Equilibrium Result Question 39

39. Which of the following statement(s) is (are) correct?

(1998, 2M)

(a) The pH of $1.0 \times 10^{-8} \mathrm{M}$ solution of HCl is $8$

(b) The conjugate base of $\mathrm{H}_2 \mathrm{PO}_4^{-}$ is $\mathrm{HPO}_4^{2-}$

(c) Autoprotolysis constant of water increases with temperature

(d) When a solution of a weak monoprotic acid is titrated against a strong base, at half-neutralisation point $ \mathrm{pH}=\left(\frac{1}{2}\right) \mathrm{p} K_a $

Show Answer

Answer:

Correct Answer: 39. ( b,c )

Solution:

  1. $\mathrm{pH}$ of $10^{-8} \mathrm{M}$ solution will be between $6$ and $7$ but never $8$ . The conjugate base of an acid is formed by removing a proton $\left(\mathrm{H}^{+}\right)$ from acid. Therefore, $\mathrm{HPO} _4^{2-}$ is a conjugate base of $\mathrm{H} _2 \mathrm{PO}^{-} _4$.

$ \mathrm{H} _2 \mathrm{O} \rightleftharpoons \mathrm{H}^{+}+\mathrm{OH}^{-} $ $\quad \quad \quad\quad\Delta H > 0$

Increasing temperature will increase equilibrium constant of the above endothermic reaction.

At the mid-point of titration $\mathrm{pH}=\mathrm{p} K _a$



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें