Chemical and Ionic Equilibrium - Result Question 41
True/False
41. If equilibrium constant for the reaction, $A _2+B _2 \rightleftharpoons 2 A B$, is $K$, then for the backward reaction $A B \rightleftharpoons \dfrac{1}{2} A _2+\dfrac{1}{2} B _2$, the equilibrium constant is $\dfrac{1}{K}$.
$(1984,1 M)$
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Answer:
Correct Answer: 41. (False)
Solution:
- It is $\dfrac{1}{\sqrt{K}}$.
BETA
