Chemical and Ionic Equilibrium - Result Question 50
50. $N _2 O _4$ is $25 %$ dissociated at $37^{\circ} C$ and one atmosphere pressure. Calculate (i) $K _p$ and (ii) the percentage dissociation at $0.1$ $ atm$ and $37^{\circ} C$.
$(1988,4 M)$
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Solution:
$ K_p=\dfrac{4 \alpha^2}{1-\alpha^2} p=\dfrac{4(0.25)^2}{1-(0.25)^2}=0.26 \mathrm{~atm} $
When $p=0.10 \mathrm{~atm}$
$ 0.26=\dfrac{4 \alpha^2(0.1)}{1-\alpha^2} \Rightarrow \alpha=0.46 $
BETA
