Chemical Bonding Result Question 1
Objective Questions I (Only one correct option)
1. During the change of $\mathrm{O} _2$ to $\mathrm{O}^{-} _2$, the incoming electron goes to the orbital.
(2019 Main, 10 April I)
(a) $\pi 2 p _x$
(b) $\pi{ }^* 2 p _x$
(c) $\pi 2 p _y$
(d) $\sigma^* 2 p_z$
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Answer:
Correct Answer: 1. ( b )
Solution:
- The change of $\mathrm{O}_2$ to $\mathrm{O}_2^{-}$ can be as follows:
So, in the formation of $\mathrm{O}_2^{-}$ from $\mathrm{O}_2$, the $17$ th electron goes to the $\stackrel{*}{\pi} 2 p_x$ or $\stackrel{*}{\pi} 2 p_y$ molecular orbital (anti-bonding) which is half-filled in $\mathrm{O}_2$.
BETA
