Chemical Bonding - Result Question 51
26. Among $KO _2, AlO _2^{-}, BaO _2$ and $NO _2^{+}$, unpaired electron is present in
(1997 C, 1M)
(a) $NO_2^{+}$ and $BaO_2$
(b) $KO _2$ and $AlO _2^{-}$
(c) Only $KO_2$
(d) Only $BaO_2$
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Answer:
Correct Answer: 26. (c)
Solution:
Molecular orbital electronic configuration is
Has one unpaired electron in $\stackrel{*}{\pi} 2 p$ orbital.
$AlO_2^{-}$ has both oxygen in $O^{2-}$ state, therefore, no unpaired electron is present.
Has no unpaired electron.
$NO_2^{+}$ has $[O=\stackrel{+}{N}=O]$ bonding, hence no unpaired electron.
BETA
