Chemical Bonding - Result Question 63
38. The hybridisation of sulphur in sulphur dioxide is
$(1986,1 M)$
(a) $s p$
(b) $s p^{3}$
(c) $s p^{2}$
(d) $d s p^{2}$
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Answer:
Correct Answer: 38. (c)
Solution:
- In $SO _2$ , the Lewis-dot structure is
$O=\ddot{S}=O$
Electron pairs at $ S = 2 ( \sigma -bonds) +1$ $(lone-pair)$ $=3$ $s p^{2}$ hybridised.
NOTE
$\pi$ -bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather $\pi$ bonds are formed by lateral overlapping of pure $p$ -orbitals.
BETA
