Some Basic Concepts of Chemistry - Result Question 15
15. An aqueous solution of $6.3$ $g$ oxalic acid dihydrate is made up to $250 mL$. The volume of $0.1 N NaOH$ required to completely neutralise $10 mL$ of this solution is
(2001,1M)
(a) $40 mL$
(b) $20 mL$
(c) $10 mL$
(d) $4 mL$
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Answer:
Correct Answer: 15. (a)
Solution:
Oxalic acid dihydrate $\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}: \mathrm{mw}=126$
It is a dibasic acid, hence equivalent weight $=63$
$\begin{aligned} \Rightarrow & \text { Normality } =\frac{6.3}{63} \times \frac{1000}{250}=0.4 \mathrm{~N} \\ \Rightarrow & N_1 V_1 =N_2 V_2 \\ \Rightarrow & 0.1 \times V_1 =0.4 \times 10 \\ \text { Hence, } & V_1 =40 \mathrm{~mL} \end{aligned}$
BETA
