Some Basic Concepts of Chemistry - Result Question 22
22. The oxidation number of phosphorus in $Ba\left(H _2 PO _2\right) _2$ is
(1988)
(a) +3
(b) +2
(c) +1
(d) -1
Show Answer
Answer:
Correct Answer: 22. (c)
Solution:
In $\mathrm{Ba}\left(\mathrm{H}_2 \mathrm{PO}_2\right)_2$, oxidation number of Ba is +2 . Therefore,
$\begin{aligned} & & \mathrm{H}_2 \mathrm{PO}_2^{-}: 2 \times(+1)+x+2 \times(-2) & =-1 \\ \Rightarrow & & x & =+1 \end{aligned}$
BETA
