Some Basic Concepts of Chemistry - Result Question 13
22. Which has maximum number of atoms?
(2003, 1M)
(a) 24 g of C (12)
(b) 56 g of $\mathrm{Fe}(56)$
(c) 27 g of $\mathrm{Al}(27)$
(d) 108 g of $\mathrm{Ag}(108)$
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Answer:
Correct Answer: 22. (a)
Solution:
- Number of atoms $=$ Number of moles $\times$ Avogadro’s number $\left(N_A\right)$
Number of atoms in $24 \mathrm{~g} \mathrm{C}=\frac{24}{12} \times N_A=2 N_A$
Number of atoms in 56 g of $\mathrm{Fe}=\frac{56}{56} N_A=N_A$
Number of atoms in 27 g of $\mathrm{Al}=\frac{27}{27} N_A=N_A$
Number of atoms in 108 g of $\mathrm{Ag}=\frac{108}{108} N_A=N_A$
Hence, 24 g of carbon has the maximum number of atoms.
BETA
