Some Basic Concepts of Chemistry - Result Question 36
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37. 3.0 g of a salt of molecular weight 30 is dissolved in 250 g water. The molarity of the solution is
(1983, 1M)
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Answer:
Correct Answer: 37. (0.4)
Solution:
$\begin{aligned} \text { Molarity } & =\frac{\text { Number of moles of solute }}{\text { Volume of solution in litre }} \\ & =\frac{\text { Weight of solute }}{\text { Molar mass }} \times \frac{1000}{\text { Volume in mL }} \\ & =\frac{3}{30} \times \frac{1000}{250}=0.4 \mathrm{M}\end{aligned}$
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