Some Basic Concepts of Chemistry - Result Question 40
44. An organic compound $X$ on analysis gives 24.24 per cent carbon and 4.04 per cent hydrogen. Further, sodium extract of 1.0 g of $X$ gives 2.90 g of silver chloride with acidified silver nitrate solution. The compound $X$ may be represented by two isomeric structures $Y$ and $Z . Y$ on treatment with aqueous potassium hydroxide solution gives a dihydroxy compound while $Z$ on similar treatment gives ethanal. Find out the molecular formula of $X$ and gives the structure of $Y$ and $Z$.
(1989,5 M)
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Solution:
- Mass of chlorine in $1.0 \mathrm{~g} X=\frac{35.5}{143.5} \times 2.9=0.717 \mathrm{~g}$
Now, the empirical formula can be derived as :
| C | H | Cl | |
|---|---|---|---|
| % wt : | 24.24 | 4.04 | 71.72 |
| Mole : | 2 | 4 | 2 |
| Simple ratio : | 1 | 2 | 1 |
$\Rightarrow$ Empirical formula $=\mathrm{CH}_2 \mathrm{Cl}$.
Because $X$ can be represented by two formula of which one gives a dihydroxy compound with KOH indicates that $X$ has two chlorine atoms per molecule.
On treatment with KOH , I will give ethane-1, 2-diol, hence it is $Y . Z$ on treatment with KOH will give ethanal as
BETA
