Some Basic Concepts of Chemistry - Result Question 8
8. In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $\mathrm{CO}_2$ is
(2019 Main, 10 Jan II)
(a) 2
(b) 5
(c) 1
(d) 10
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Answer:
Correct Answer: 8. (c)
Solution: Reaction of oxalate with permanganate in acidic medium.
$$ \begin{array}{lccc} & 5 \mathrm{C}_2 \mathrm{O}_4^{2-}+2 \mathrm{MnO}_4^{-} & 10 \mathrm{CO}_2+2 \mathrm{Mn}^{2+}+8 \mathrm{H}_2 \mathrm{O} \\ n \text {-factor : } & (4-3) \times 2=2 & (7-2)=5 & \\ \text { Number of mole } & 5 & 2 & 10 \end{array} $$
$\Rightarrow 5 \mathrm{C}_2 \mathrm{O}_4^{2-}$ ions transfer $10 e^{-}$to produce 10 molecules of $\mathrm{CO}_2$.
So, number of electrons involved in producing 10 molecules of $\mathrm{CO}_2$ is 10 . Thus, number of electrons involved in producing 1 molecule of $\mathrm{CO}_2$ is 1 .
BETA
